Partition Of Land 1p6p3n
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1
CASE I: DIVIDING AN AREA INTO TWO PARTS BY A LINE BETWEEN TWO POINTS PROBLEM:
Given the following data of a tract of land, determine the area of the two parts into which the tract is divided by a line running from F to C. Calculate the length and bearing of the dividing line. Line Length Bearing AB 650 m N 15 o 30 ' E BC
600
N 75 o 40' E
CD
550
S 80o 10' E
DE
700
S 20o 10 ' W
EF
600
N 76 o 30' W
FA
499.8 5
S 70o 51' 5'' W
SOLUTION:
C
N
1. Solving for thearea of the whole traverse (tract ABCDEF ) .
Tarlac State University Course: CE 313 – Surveying 1 COLLEGE OF ENGINEERING Engr. Randy G. Policarpio Civil Engineering Department 10:46:50 PM
Prepared by: 12/3/2015
2 Page
A ABCDEF =
1 ( Double Area ) 2 ∑
1 A ABCDEF = (1,355,224.67 ) 2 A ABCDEF =677,612.34 sq . m .
2.Consider tract FABC
C
3. Solving for the Length∧Bearing of the Dividing Line C
Tarlac State University Course: CE 313 – Surveying 1 COLLEGE OF ENGINEERING Engr. Randy G. Policarpio Civil Engineering Department 10:46:50 PM
F
Prepared by: 12/3/2015
3 Page
LCF =√ ( 610.94 ) + ( 282.83 ) =673.23 m 2
θCF =tan−1
2
=24 50 ( 282.83 610.94 ) o
'
o
'
Bearing of the Dividing Line CF: S 24 50 W 4. Solving for the area of Tract FAB
C
1 A FABC= ( 580421.15 ) 2 A FABC=290,210.575 sq . m.
5.Consider tract CDEF
Tarlac State University Course: CE 313 – Surveying 1 COLLEGE OF ENGINEERING Engr. Randy G. Policarpio Civil Engineering Department 10:46:50 PM
Prepared by: 12/3/2015
4 Page
6. Solving for the Length∧Bearing of the Dividing Line FC
LFC = √( 610.94 ) + (282.83 ) =673.23 m 2
θ FC =tan −1
2
=24 50 ( 282.83 610.94 ) o
'
Bearing of the Dividing Line CF: N 24 o 50' E 7. Solving for thearea of Tract CDEF
Tarlac State University Course: CE 313 – Surveying 1 COLLEGE OF ENGINEERING Engr. Randy G. Policarpio Civil Engineering Department 10:46:50 PM
Prepared by: 12/3/2015
5 Page
1 A CDEF = ( 774,803.53 ) 2 A CDEF =387,401.765 sq .m .
Checking :
A FABC + A CDEF = A ABCDEF 290,210.575+387,401.765=677, 612.34 677, 612.34=677, 612.34 therefore OK
CASE II: DIVIDING AN AREA BY A LINE RUNNING THROUGH A POINT AND A GIVEN DIRECTION PROBLEM: Given the following data of a tract of land, find the area of each of the two parts into which the tract is divided by a line through F with a bearing of Line AB
Length 650 m
N 15 o 30 ' E
BC
600
N 75 o 40' E
CD
550
S 80o 10' E
DE
700
S 20o 10 ' W
N 35o 30 ' E .
Bearing
Tarlac State University Course: CE 313 – Surveying 1 COLLEGE OF ENGINEERING Engr. Randy G. Policarpio Civil Engineering Department 10:46:50 PM
Prepared by: 12/3/2015
N 76 o 30' W
FA
499.8 5
S 70o 51' 5'' W
6
600
Page
EF
SOLUTION:
C
P
1. Solving for thearea of the whole traverse (tract ABCDEF ) .
A ABCDEF =
1 ( Double Area ) 2 ∑
1 A ABCDEF = (1,355,224.67 ) 2 Tarlac State University Course: CE 313 – Surveying 1 COLLEGE OF ENGINEERING Engr. Randy G. Policarpio Civil Engineering Department 10:46:50 PM
Prepared by: 12/3/2015
Page
7
A ABCDEF =677,612.34 sq . m .
2.Consider tract FABC
C
3. Solving for the Length∧Bearing of the Trial Line C
F
LCF =√ ( 610.94 ) + ( 282.83 ) =673.23 m 2
θCF =tan−1
2
=24 50 ( 282.83 610.94 ) o
'
Bearing of theTrial Line CF :S 24o 50' W Tarlac State University Course: CE 313 – Surveying 1 COLLEGE OF ENGINEERING Engr. Randy G. Policarpio Civil Engineering Department 10:46:50 PM
Prepared by: 12/3/2015
8 Page
2.Consider tract F
f =¿ λ β
673.23 m ρ
c=¿
Tarlac State University Course: CE 313 – Surveying 1 COLLEGE OF ENGINEERING Engr. Randy G. Policarpio Civil Engineering Department 10:46:50 PM
Prepared by: 12/3/2015
1
CASE I: DIVIDING AN AREA INTO TWO PARTS BY A LINE BETWEEN TWO POINTS PROBLEM:
Given the following data of a tract of land, determine the area of the two parts into which the tract is divided by a line running from F to C. Calculate the length and bearing of the dividing line. Line Length Bearing AB 650 m N 15 o 30 ' E BC
600
N 75 o 40' E
CD
550
S 80o 10' E
DE
700
S 20o 10 ' W
EF
600
N 76 o 30' W
FA
499.8 5
S 70o 51' 5'' W
SOLUTION:
C
N
1. Solving for thearea of the whole traverse (tract ABCDEF ) .
Tarlac State University Course: CE 313 – Surveying 1 COLLEGE OF ENGINEERING Engr. Randy G. Policarpio Civil Engineering Department 10:46:50 PM
Prepared by: 12/3/2015
2 Page
A ABCDEF =
1 ( Double Area ) 2 ∑
1 A ABCDEF = (1,355,224.67 ) 2 A ABCDEF =677,612.34 sq . m .
2.Consider tract FABC
C
3. Solving for the Length∧Bearing of the Dividing Line C
Tarlac State University Course: CE 313 – Surveying 1 COLLEGE OF ENGINEERING Engr. Randy G. Policarpio Civil Engineering Department 10:46:50 PM
F
Prepared by: 12/3/2015
3 Page
LCF =√ ( 610.94 ) + ( 282.83 ) =673.23 m 2
θCF =tan−1
2
=24 50 ( 282.83 610.94 ) o
'
o
'
Bearing of the Dividing Line CF: S 24 50 W 4. Solving for the area of Tract FAB
C
1 A FABC= ( 580421.15 ) 2 A FABC=290,210.575 sq . m.
5.Consider tract CDEF
Tarlac State University Course: CE 313 – Surveying 1 COLLEGE OF ENGINEERING Engr. Randy G. Policarpio Civil Engineering Department 10:46:50 PM
Prepared by: 12/3/2015
4 Page
6. Solving for the Length∧Bearing of the Dividing Line FC
LFC = √( 610.94 ) + (282.83 ) =673.23 m 2
θ FC =tan −1
2
=24 50 ( 282.83 610.94 ) o
'
Bearing of the Dividing Line CF: N 24 o 50' E 7. Solving for thearea of Tract CDEF
Tarlac State University Course: CE 313 – Surveying 1 COLLEGE OF ENGINEERING Engr. Randy G. Policarpio Civil Engineering Department 10:46:50 PM
Prepared by: 12/3/2015
5 Page
1 A CDEF = ( 774,803.53 ) 2 A CDEF =387,401.765 sq .m .
Checking :
A FABC + A CDEF = A ABCDEF 290,210.575+387,401.765=677, 612.34 677, 612.34=677, 612.34 therefore OK
CASE II: DIVIDING AN AREA BY A LINE RUNNING THROUGH A POINT AND A GIVEN DIRECTION PROBLEM: Given the following data of a tract of land, find the area of each of the two parts into which the tract is divided by a line through F with a bearing of Line AB
Length 650 m
N 15 o 30 ' E
BC
600
N 75 o 40' E
CD
550
S 80o 10' E
DE
700
S 20o 10 ' W
N 35o 30 ' E .
Bearing
Tarlac State University Course: CE 313 – Surveying 1 COLLEGE OF ENGINEERING Engr. Randy G. Policarpio Civil Engineering Department 10:46:50 PM
Prepared by: 12/3/2015
N 76 o 30' W
FA
499.8 5
S 70o 51' 5'' W
6
600
Page
EF
SOLUTION:
C
P
1. Solving for thearea of the whole traverse (tract ABCDEF ) .
A ABCDEF =
1 ( Double Area ) 2 ∑
1 A ABCDEF = (1,355,224.67 ) 2 Tarlac State University Course: CE 313 – Surveying 1 COLLEGE OF ENGINEERING Engr. Randy G. Policarpio Civil Engineering Department 10:46:50 PM
Prepared by: 12/3/2015
Page
7
A ABCDEF =677,612.34 sq . m .
2.Consider tract FABC
C
3. Solving for the Length∧Bearing of the Trial Line C
F
LCF =√ ( 610.94 ) + ( 282.83 ) =673.23 m 2
θCF =tan−1
2
=24 50 ( 282.83 610.94 ) o
'
Bearing of theTrial Line CF :S 24o 50' W Tarlac State University Course: CE 313 – Surveying 1 COLLEGE OF ENGINEERING Engr. Randy G. Policarpio Civil Engineering Department 10:46:50 PM
Prepared by: 12/3/2015
8 Page
2.Consider tract F
f =¿ λ β
673.23 m ρ
c=¿
Tarlac State University Course: CE 313 – Surveying 1 COLLEGE OF ENGINEERING Engr. Randy G. Policarpio Civil Engineering Department 10:46:50 PM
Prepared by: 12/3/2015
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